Calculate Mass of P in Apatite - 211.866kg

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The discussion focuses on calculating the mass of pure phosphorus (P) in 1150 kg of apatite, with the molar mass of apatite given as 504.31 g/mol. The calculation shows that the mass of phosphorus in the apatite is approximately 211.866 kg. The importance of using the molar mass in the calculation is highlighted, as it is essential for determining the amount of phosphorus present. Additionally, participants are advised against opening multiple threads on the same topic to avoid confusion. The thread emphasizes the relevance of accurate molar mass in chemical calculations.
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Homework Statement


Apatite (Ca5(PO4)3F) is used to manufacture fertilizer.

Homework Equations


How many kilograms of pure phosphorus (P) is included in 1150 kg of apatite?

The Attempt at a Solution


mp/(3*30.97) = 1150000/504.31
mp= 211866.709g =211.866Kg
 
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Where is the apatite's molar mass involved ?

I saw you had already opened a thread on the same subject. Well, don't ever do that, even if you think the received answers are not satisfactory.

Thanks.
 
Molar mass is 504.31g/mol
 

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