How do I calculate mass of pulley and force of friction on AtwoodMach.

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SUMMARY

This discussion focuses on calculating the mass of a pulley and the force of friction in an Atwood machine setup using experimental data. The equation used is (m1 - m2)g = (m1 + m2 + mp)a + f, where m1 and m2 are the masses on either side, mp is the mass of the pulley, and f is the frictional force. The participant derived a slope of 143.28 from their Fnet vs Acceleration plot, leading to the conclusion that the pulley mass mp is 28.5g and the frictional force f is 323.24 dynes. The participant also explored a second method to calculate friction, resulting in a value of 4950, which raised concerns about unit consistency.

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francisco300
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Homework Statement


Basically, I need to calculate the mass of the pulley and friction using data that I collected.


Homework Equations


I was given: (m1 - m2)g = (m1 + m2 + mp)a + f


The Attempt at a Solution



For the first part, I collected data using a sensor to find the acceleration. I kept the total mass attached to each cup on each side of the machine constant but changed the difference in their masses by 10g each run.

After 6 runs, I plotted my data of Fnet vs Acceleration. Fnet is (m1 - m2)g (I converted g into dynes). When I get my slope, the lab manual says that i should "expect our plot of (m1 - m2)g vs a to have a slope larger than (m1 - m2)g by an amount equal to the effective mass of the pulley mp and a positive intercept equal to the frictional force f"

My equation turned out to be y = 143.28x + 323.24 (i used best fit line).

This means 143.28 = m1 + m2 + mp
In which case mp= 28.5g right?

Then the force of friction should = 323.4 right?
Is the unit in dynes?


For part b, did the same procedure but kept the net force constant instead of the total mass. I gathered my data and plotted

1/a vs m1 + m2

I got y = 0.0002x + 0.0059 as my best fit line

Now I have to use this equation to find the force of friction

1/a = ((m1 + m2) )/((m1-m2)g-f) + mp/((m1-m2)g-f)


But i get 4950 which I believe is in Netwons and that would be too much considering 323 dynes = 0.00323 Newtons
 

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You seem to be working the equations correctly - they may be the wrong equations of course, so you should check that you understand them. Don't just assume they are right: check!

The first thing you need to do is check those units - do that by dimensional analysis.
 

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