Chemistry Calculate persistence length of a single dsDNA molecule

AI Thread Summary
The discussion focuses on calculating the persistence length (P) of a single dsDNA molecule using force (F) versus extension (x) data obtained from optical tweezers. The calculated persistence length of approximately 2.9 nm is significantly lower than the expected value of around 50 nm. The user attempted to fit the data linearly after converting the force data to F^{-1/2}, but encountered issues with the slope being too low. A correction was suggested regarding the interpolation formula used, indicating a potential error in the equation. Further examination of the equation and data plots is recommended to identify the source of the discrepancy.
pen
Messages
6
Reaction score
0
Hello!

1. The problem statement and all variables

AIM: Calculating persistence length P of a single dsDNA molecule from a data set of force F (to the molecule) vs. extension x measurements. Experimental background: pN forces were applied to a single dsDNA molecule spanned between two μm-beads using an optical tweezer.

PROBLEM: When I calculate P, I get values of about 2.9 nm, which is far below the expected value for P of dsDNA, which is about 50nm.

Homework Equations



The calculation was done as follows: For a chosen force range the F-data were converted to F^{-1/2} and plotted vs. x. The data points were fitted linearly.

According to an interpolation formula the extension x of a worm like chain with contour length L_0 (Bustamante et al.,1994) is:

\frac{FP}{k_BT}=\frac{1}{4}(1−\frac{x}{L_0})−2−\frac{1}{4}+\frac{x}{L_0},

applicable for a force range of ~5-15pN, where the molecule reveals a linear F-x relationship (like a Hookean spring).

From that follows that the y-intercept of the straight line fitted to the data points is 2\sqrt{\frac{P}{k_BT}}.

The Attempt at a Solution



The problem is (as I think) that the slope of the fitted straight line is too low. So I chose different force-ranges, as I thought, that the chosen force range might be wrong. But that didnt work. In the attachement of the thread "Calculate persistence length from force extension data of a single DNA" one can find the force curve and a F^{-1/2}-x graph, plotted for a force range of 6-16pN, with the linear fit: slope of -1.5151, the y-intercept at 1.6931 and a calculated persistence length of 2.9455 nm

I really would appreciate some help

Pen
 
Last edited:
Physics news on Phys.org
pen said:
Hello!

1. The problem statement and all variables

AIM: Calculating persistence length P of a single dsDNA molecule from a data set of force F (to the molecule) vs. extension x measurements. Experimental background: pN forces were applied to a single dsDNA molecule spanned between two μm-beads using an optical tweezer.

PROBLEM: When I calculate P, I get values of about 2.9 nm, which is far below the expected value for P of dsDNA, which is about 50nm.

Homework Equations



The calculation was done as follows: For a chosen force range the F-data were converted to F^{-1/2} and plotted vs. x. The data points were fitted linearly.

According to an interpolation formula the extension x of a worm like chain with contour length L_0 (Bustamante et al.,1994) is:

\frac{FP}{k_BT}=\frac{1}{4}(1−\frac{x}{L_0})−2−\frac{1}{4}+\frac{x}{L_0},

applicable for a force range of ~5-15pN, where the molecule reveals a linear F-x relationship (like a Hookean spring).

From that follows that the y-intercept of the straight line fitted to the data points is 2\sqrt{\frac{P}{k_BT}}.

The Attempt at a Solution



The problem is (as I think) that the slope of the fitted straight line is too low. So I chose different force-ranges, as I thought, that the chosen force range might be wrong. But that didnt work. In the attachement of the thread "Calculate persistence length from force extension data of a single DNA" one can find the force curve and a F^{-1/2}-x graph, plotted for a force range of 6-16pN, with the linear fit: slope of -1.5151, the y-intercept at 1.6931 and a calculated persistence length of 2.9455 nm

I really would appreciate some help

Pen

I know approximately nothing about this subject, but the equation quoted relating F and x which I gather are your experimental parameters is linear so I don't understand how a square root could enter your calculation of an intercept. I wonder at a formula that contains 1/4 - 1/4.
 
Hello Epenguin!

Sorry, my mistake: it should be \big(1-\frac{x}{L_0}\Big)^{-2} instead of \big(1-\frac{x}{L_0}\Big) in the equation.
 
Too much guessing needed now, maybe if you quoted the equation and showed the plot something might become apparent.
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
I don't get how to argue it. i can prove: evolution is the ability to adapt, whether it's progression or regression from some point of view, so if evolution is not constant then animal generations couldn`t stay alive for a big amount of time because when climate is changing this generations die. but they dont. so evolution is constant. but its not an argument, right? how to fing arguments when i only prove it.. analytically, i guess it called that (this is indirectly related to biology, im...
Back
Top