Calculate power lossess against road gradients

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To calculate power losses for a 60 cc single-cylinder water-cooled engine on a 5% road gradient, determine the vehicle's vertical speed by multiplying the total speed (30 km/h) by the gradient. The required power can be calculated using the formula P_req = M * g * V_h, where M is the vehicle's mass and g is the acceleration due to gravity. The engine's displacement and cooling system are not relevant for this calculation. This analysis is part of a school project involving the construction of a three-wheeler car. Understanding these calculations is essential for accurately estimating the engine's performance on inclines.
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i want to calcculate the power lossess of a 60 cc single cylinder water cooled engine against the 5% road gradients.can anyone help?
 
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Carvinos said:
i want to calcculate the power lossess of a 60 cc single cylinder water cooled engine against the 5% road gradients.can anyone help?

Welcome to the PF.

What is the context of your question? What vehicle is this small engine in? What speed is the vehicle moving? Is this just a paper calculation, a simulation, or do you intend to build it for a school project?
 
To calculate the power required to drive up a hill at a certain speed, calculate the vehicle's vertical speed (speed*grade), and then multiply by the vehicle's mass and G. The engine's dispplacement and cooling are not relevant in this problem.

V_{h}=V_{tot}*Grade

P_{req}=M*g*V_{h}
 
thnx for ur response.this is basically a school project and we have to build a three wheeler car, 2 wheels at the front and one at the rear and it is to be driven at 30kmph.thnx a lot once again.
 

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