Calculate Refraction of Red Light Wavelength 750nm

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To calculate the wavelength of red light in a liquid, the index of refraction is determined using Snell's Law: n1sin(theta1) = n2sin(theta2). Given the angle of incidence at 39 degrees and the angle of refraction at 17 degrees, the index of refraction for the liquid can be calculated. The wavelength in the liquid can then be found using the formula n = wavelength1/wavelength2, where the wavelength in air is 750nm. The calculated wavelength of red light in the liquid is approximately 349nm. Understanding these principles is essential for accurate refraction calculations.
shorty_47_2000
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Red light travels from air into liquid at an angle of incidence of 39 degrees and an angle of reflection of 17 degrees. Calculate the wavelength of the red light in the liquid if it's wavelength in the air is 750nm. If someone coule tell me how to go about this question that would be very helpful, thanks.
 
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I believe you use n1sin theta1 = n2sin theta2 to find out the index of refraction for the liquid and then use n = wavelength1/wavelength2

Dang i need to learn how to use latex.
 
Thanks for the equation, the answer I received was 349nm. I think that sounds about right.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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