Calculate Repulsive Force of 2 Protons in Atom

Thread starter lilkrazyrae
Start date Feb 7, 2006
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Force

AI Thread Summary

The discussion focuses on calculating the repulsive force between two protons in an atom, given their separation of 1.00 x 10^-15m. The formula used is F=k |q(1)|^2 / r^2, leading to a calculated force of 230.7N. While the final answer appears correct, there are noted mistakes in the formula's presentation. The conversation emphasizes the importance of accurate formula representation in physics calculations. Overall, the calculation aligns with the expected results for the repulsive force between protons.

Feb 7, 2006

lilkrazyrae

Find the repulsive force on two protons in the nucleus of an atom assuming they are separated by the minimum distance of 1.00 x 10^-15m.

So F=k lq(1)l^2/ r^2
=8.99 x 10^9 (1.602 x 10 ^-19)^2/(1.00 x 10^15m)
=230.7N

Is this correct?

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Feb 8, 2006

SpaceTiger

Staff Emeritus

Science Advisor

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lilkrazyrae said:

Is this correct?

Answer looks right to me, though you made several mistakes in writing out the formula.

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