Calculate resultants of two forces

  • Thread starter Thread starter zeralda21
  • Start date Start date
  • Tags Tags
    Forces
Click For Summary
SUMMARY

The discussion focuses on calculating the resultant of two vertical forces acting on a beam, specifically determining where the resultant force acts. The user calculated the x and y components of the resultant force, concluding that R_{x}=0 and R_{y}=-20, resulting in a magnitude of 20N. The key challenge is understanding how to replace the two forces with a single equivalent force at a specific location, particularly in relation to point A, which is crucial for analyzing moments created by the forces.

PREREQUISITES
  • Understanding of vector components in physics
  • Knowledge of force and moment calculations
  • Familiarity with equilibrium concepts in statics
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the principles of static equilibrium in mechanics
  • Learn about calculating moments about a point in a beam
  • Explore vector addition and resultant forces in physics
  • Review examples of force systems and their equivalent representations
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and statics, as well as engineers involved in structural analysis and force calculations.

zeralda21
Messages
119
Reaction score
1

Homework Statement



Where does the resultant of the two forces act?

http://i.imgur.com/CBO8fi2.jpg

Homework Equations



None really. Basic algebra for calculating resultants.

The Attempt at a Solution



First off, I have tried to calculate the x and y components of the resultant, call it R. Here I think that R_{x}=0 (both forces are vertical) and R_{y}=-20 (net force in the y-direction). So the resultant is:

R=R_{x}+R_(y} = 0x-20y with magnitude of 20N. However, I am unable to understand how the lengths will help me.
 
Last edited:
Physics news on Phys.org
The question wants you to replace the two forces at different distances with one force that has the same effect. So - what is the effect of each force as drawn? (Hint: what is special about point A?)
 
Simon Bridge said:
The question wants you to replace the two forces at different distances with one force that has the same effect. So - what is the effect of each force as drawn? (Hint: what is special about point A?)

That is what I have tried to do actually. I have replaced them with one downward force with magnitude 20N. But I don't know where it is located.

What is special about point A? Well, not sure. There must be a force to compensate the downward force but that is done by the beam(object).
 
20N is what you'd get if the forces acted along the same line.
Do they?

Won't each of the two forces create a moment about point A?
 
Simon Bridge said:
20N is what you'd get if the forces acted along the same line.
Do they?

Won't each of the two forces create a moment about point A?

Yes, I suppose. I will have to think a little bit about this one before I answer. Not sure about the theory yet.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
Replies
3
Views
1K
Replies
4
Views
1K
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
11
Views
1K
Replies
4
Views
815
  • · Replies 7 ·
Replies
7
Views
2K
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K