Calculate Sunset Local Time: 36N, 6E | Hour Angle, Declination Angle & More!

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SUMMARY

The discussion focuses on calculating the sunset local time for a specific location at latitude 36N and longitude 6E. The user initiated the calculation with an hour angle of 86.25 degrees and attempted to determine the declination angle, which was found to be -5.144 degrees. However, the user faced challenges due to the lack of the day number and month, which are essential for accurate calculations. The time correction factor was established as 1 hour, indicating the need for precise data to complete the sunset time calculation.

PREREQUISITES
  • Understanding of hour angle calculations in solar position astronomy
  • Knowledge of declination angle and its significance in solar altitude
  • Familiarity with the equation of time and its application
  • Basic concepts of solar time and local time adjustments
NEXT STEPS
  • Research how to calculate the day number for solar declination angle
  • Learn about the equation of time and its impact on solar calculations
  • Explore methods for determining solar altitude angles at sunset
  • Investigate tools for calculating solar positions, such as the Solar Position Algorithm (SPA)
USEFUL FOR

Astronomers, solar energy engineers, and anyone interested in precise solar position calculations will benefit from this discussion.

antonyda
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calculate the sunset local time for a location : latitude = 36 N , longitude = 6 E
if the apparent solar time at this moment was 17h,45 , and ?
i started with hour angle h = 86.25 , after that i tried to determine the declination angle d but i don't have the day number and the month , also that for equation of time i can't determine and for the solar altitude angle =0 since for sunset and sunrise so i calculated the declination angle of solar altitude relation and i get a d= -5.144 and when i tried to calculate the day number of declination angle i had a negative value and that's wrong
so what to do
 
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the time correction factor = 1 hour
 

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