Calculate Tension in Rope: Principle of Moments Homework

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The discussion revolves around calculating the tension in a rope supporting a beam, with initial calculations yielding a tension of 92N based on torque equations. The user mistakenly calculated the torque, leading to confusion when the textbook stated the tension should be 100N. Other participants suggested checking arithmetic as a common source of error. The user acknowledged the mistake and expressed gratitude for the assistance. The conversation highlights the importance of careful calculations in physics problems.
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Homework Statement


Calculate the tension in the rope, T, in the diagram below: http://imageshack.com/a/img905/2848/yMC01l.png

Homework Equations

The Attempt at a Solution


The 'beam' is a stable structure, thus the resultant forces be equal that are acting upon the beam. So,
I calculated the the Torque from the mass as being 150N * 0.6m + 100N * 0.3m = 110 Nm, setting this equal to the Torque generated by the 'force line' from the rope, T*1.2m = 110Nm, thus T rounded to the nearest Newton is = 92N. I Felt fairly confident with this until my textbook said the tension in the rope is = to 100N. Can anybody clear this up for me and explain where I went wrong, Thanks!.
 
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Marcus27 said:
150N * 0.6m + 100N * 0.3m = 110 Nm
Check your arithmetic, that's "the usual suspect."
 
Ah, thank you. I did not spot that mistake, sorry for wasting your time. Not a great first post on my part o:)
 
Do not let it ruin your day --- we've all been there.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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