Calculate the flux through a cube of size 1.0 m

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Homework Help Overview

The discussion revolves around calculating the electric flux through a cube in the presence of a given electric field described by the equation \(\bar{E} = \hat{i}xy^2\). The original poster seeks guidance on how to approach the problem, particularly in understanding the implications of the electric field's description and the calculation of flux.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the formula for electric flux, noting that the simple form \(\Phi = EA\) applies under specific conditions. Questions arise regarding the integration of the electric field over the surface and the meaning of the notation used, such as \(\hat{i}\) and \(\hat{n}\). There is also a mention of the need to understand the basics of the subject matter.

Discussion Status

The discussion is ongoing, with participants exploring different aspects of the problem. Some guidance has been offered regarding the conditions under which the simpler flux equation applies, and there is an acknowledgment of the need for foundational understanding. However, there is no explicit consensus on how to proceed with the calculations.

Contextual Notes

The original poster indicates a lack of familiarity with the material due to joining the class late, which may contribute to their uncertainty in approaching the problem. There is also a sense of urgency as the assignment is due soon.

junglebobo
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An E field exists in a region of space and it can be described by:
[tex]\bar{E} = \hat{i}xy^2[/tex]

Calculate the flux through a cube of size 1.0m, with one end extending into the positive x,y and z directions.

Find the charge enclosed.

I have no idea how to start this? can someone point me in the right direction please?

I know that:
[tex]\Phi = EA[/tex]

But what does it mean that the E field exists in a region of space?

All help is appreciated.

And I am not looking for a solution, but all help will be appreciated.

Cheers
 
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junglebobo said:
I know that:
[tex]\Phi = EA[/tex]

This applies only if ##\vec E## has the same magnitude everywhere on the surface, and is perpendicular to the surface everywhere. If these are not true, you have to integrate:

$$\Phi = \int {\vec E \cdot \hat n da}$$

Does this ring a bell?
 
Sorry, not really.
What values do I put in for for [itex]\hat{i}[/itex]?
And what's the [itex]\hat{n}[/itex]? And do I pull E out of the integration as a constant? Then integrate da just to a?
I'm sorry, I just got into this class two weeks late, and this is due tomorrow. But I'm going to spend this week catching up.
 
Last edited by a moderator:
You really just need to sit down with your textbook and learn the basics. After all, if you don't even understand what the notation means, how can you expect to solve the problem? The examples in your textbook should answer most of your questions.
 

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