Calculate the following line integral

lep11
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Homework Statement


Let ##f(x,y)=(xy,y)## and ##\gamma:[0,2\pi]\rightarrowℝ^2##,##\gamma(t)=(r\cos(t),r\sin(t))##, ##r>0##. Calculate ##\int_\gamma{f{\cdot}d\gamma}##.

Homework Equations

The Attempt at a Solution


The answer is 0. Here's my work. However, this method requires that you are familiar with some useful trig identities.
2cpuy6v.jpg


Could someone please take a look at it and check if it's correct? Are there alternative ways? I have also tried to find the potential function ##u##, ##\nabla{u}=f##...
 
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lep11 said:

Homework Statement


Let ##f(x,y)=(xy,y)## and ##\gamma:[0,2\pi]\rightarrowℝ^2##,##\gamma(t)=(r\cos(t),r\sin(t))##, ##r>0##. Calculate ##\int_\gamma{f{\cdot}d\gamma}##.

Homework Equations

The Attempt at a Solution


The answer is 0. Here's my work. However, this method requires that you are familiar with some useful trig identities.
2cpuy6v.jpg


Could someone please take a look at it and check if it's correct? Are there alternative ways? I have also tried to find the potential function ##u##, ##\nabla{u}=f##...

I get an answer of 0 as well, but I have not checked your work because I do not look at posted images, but only at typed versions.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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