Calculate the force required to pull the truck

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The discussion revolves around calculating the forces involved in moving a 110 kg trunk across a floor. The coefficient of kinetic friction was calculated as 0.35 using the formula μk = Fk/Fn, where Fk is the applied force and Fn is the normal force. For part b, the impact of a friend pulling with 150N upwards on the trunk's movement is questioned, suggesting the need for a free-body diagram to analyze the forces accurately. In part c, the force required to maintain constant velocity with a 55 kg friend sitting on the trunk was calculated to be 566N. The conversation emphasizes the importance of free-body diagrams for understanding the forces at play.
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Homework Statement


You are dragging a 110 kg trunk across a floor at a constant velocity with a horizontal force of 380N.
a) Calculate the coefficient of kinetic friction
b)A friend decides to help by pulling on the truck with a force of 150N [up]. Will this help? Calculate the force required to pull the truck at a constant velocity to help you decide.
c) Instead of pulling on the trunk, your 55 kg friend just sits on it. What force is required to keep the trunk moving at a constant velocity?

Homework Equations


μ=Ff/Fn

The Attempt at a Solution



a) μk= Fk/Fn
= 380/(110x9.8)
μk = 0.35

b)

c) Fk = μkFn
= (0.35)(165x9.8)
Fk = 566N

Did I solve a) and c) correctly? Also how would I go about doing b).
 
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(a) sort of - you should start from a free-body diagram, which makes the equations look different.
(b) use a free-body diagram
(c) again - sort of - same reason. Where did you get that relationship from? (i.e. to add the masses.)
 
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