Calculate the mass of the air in the cylinder

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SUMMARY

The discussion centers on calculating the mass of air in a vertical cylinder with a heavy piston, given specific conditions: a temperature of 300 K, pressure of 250 kPa, and volume of 0.350 m³. Participants confirmed that the number of moles (n) can be calculated using the ideal gas law, n = PV/RT, leading to a result of approximately 35.098 mol. The mass of air was then determined by multiplying the number of moles by the molar mass of air (28.9 g/mol), yielding a mass of approximately 1.014 kg.

PREREQUISITES
  • Understanding of the ideal gas law (PV = nRT)
  • Knowledge of specific heat capacities (CV = 5R/2)
  • Familiarity with unit conversions (e.g., g/mol to kg)
  • Basic thermodynamics concepts related to constant volume and constant pressure processes
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  • Study the calculation of work done in constant pressure processes
  • Explore the relationship between temperature, pressure, and volume in gas laws
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This discussion is beneficial for students and professionals in thermodynamics, mechanical engineering, and physics, particularly those working with gas laws and energy calculations in closed systems.

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A vertical cylinder with a heavy piston contains air at a temperature of 300 K. The initial pressure is 250 kPa and the initial volume is 0.350 m^3. Take the molar mass of air as 28.9 g/mol and assume that CV = 5R / 2.
(b) Calculate the mass of the air in the cylinder.
I know I have to use the volume that they provided me and the molar mass of air to somehow calculate the mass of the air in cylinder. Could someone please give me a hint in the right direction?
 
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lunarskull said:
Take the molar mass of air as 28.9 g/mol and assume that CV = 5R / 2.

(b) Calculate the mass of the air in the cylinder.

Do you have sufficient information to find the number of moles, n, in the cylinder?
 
dynamicsolo said:
Do you have sufficient information to find the number of moles, n, in the cylinder?

I am not sure I do, maybe I could figure out how many moles are in 1 liter? Otherwise, I suppose I could calculate the specific heat into kj/kg*K to get the kg units, but I am not sure that would help all that much.
 
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lunarskull said:
I am not sure I do, maybe I could figure out how many moles are in 1 liter? Otherwise, I suppose I could calculate the specific heat into kj/kg*K to get the kg units, but I am not sure that would help all that much.

Won't n = PV/RT?

What are the other parts of this problem?
 
dynamicsolo said:
Won't n = PV/RT?

What are the other parts of this problem?

Thanks a lot for the help, i figured out the answer to part b of this question along with parts (a) and (c). I am stuck on part (d) now though...

The questions and answers to the respective problems are listed below:


(a) Find the specific heat of air at constant volume in units of kJ/kg·K.

.71 kg/ j*K

(b) Calculate the mass of the air in the cylinder.

(c) Suppose the piston is held fixed. Find the energy input required to raise the temperature of the air to 700 K.

291.7 J

(d) Assume again the conditions of the initial state and that the heavy piston is free to move. Find the energy input required to raise the temperature to 700 K.

I would use n* deltaT * 5R/2 to calculate this, but I am not sure how to calculate how much more energy I would need if the "heavy" piston is free to move.
 
lunarskull said:
(c) Suppose the piston is held fixed. Find the energy input required to raise the temperature of the air to 700 K.

291.7 J

(d) Assume again the conditions of the initial state and that the heavy piston is free to move. Find the energy input required to raise the temperature to 700 K.

I would use n* deltaT * 5R/2 to calculate this, but I am not sure how to calculate how much more energy I would need if the "heavy" piston is free to move.

That's what you'd use for part (c) also. Since it's a constant volume process, Q = delta-U = (5/2) · nR · delta T. What did you find for n?

For part (d), letting the piston move freely means that the force applied by the gas pressure balances the weight of the piston. In other words, this is a constant-pressure process. While delta-U is again (5/2) · nR · delta T, you now need to find the work done in this process with the volume going to its new value (which must also be found) in order to determine the heat input.
 
dynamicsolo said:
That's what you'd use for part (c) also. Since it's a constant volume process, Q = delta-U = (5/2) · nR · delta T. What did you find for n?

For part (d), letting the piston move freely means that the force applied by the gas pressure balances the weight of the piston. In other words, this is a constant-pressure process. While delta-U is again (5/2) · nR · delta T, you now need to find the work done in this process with the volume going to its new value (which must also be found) in order to determine the heat input.

n came out to be 35.098 mol which i multiplied by .0289 kg/mol to get the mass in kg. How would i calculate the new volume though?
 
lunarskull said:
A vertical cylinder with a heavy piston contains air at a temperature of 300 K. The initial pressure is 250 kPa and the initial volume is 0.350 m^3.

(d) Assume again the conditions of the initial state and that the heavy piston is free to move. Find the energy input required to raise the temperature to 700 K.

How would i calculate the new volume though?

You know the pressure remains at 250 kPa and you have the number of moles and the new temperature. So V' = nRT'/P .

BTW, while I agree with your result for n, I rather think that the answer to part (c) is somewhat more than 292 J...

[EDIT: This wouldn't happen to be Problem 17.33 in Serway & Jewett, would it? I just spotted it in the book when I met some of my students today...]
 
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