Calculate the total energy of the mass spring system

AI Thread Summary
The total energy of the mass-spring system is calculated to be 1.6 Joules using the formula ET = 0.5 * k * A^2. The maximum speed of the mass is determined to be 0.52 m/s, derived from the energy equation. When the mass is 5.0 cm from the equilibrium point, its speed is calculated to be 0.45 m/s. The calculations and methods used for these values are confirmed to be correct. This analysis effectively demonstrates the principles of simple harmonic motion in a mass-spring system.
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Homework Statement


A 12Kg mass udnergoes simple harmonic motion with an amplitude of 10cm. If the force constant for the spring is 320 N/m

a) Calculate the total energy of the mass spring system.
b) Calculate the maximum speed of the mass
c) Calculate the speed of the mass when it is 5.0cm from the equilibrium point.


Homework Equations



Fx= -kx
a=kx/m
ET=(0.5)mv^2 +(0.5)kx^2
Et=(0.5)(m)(A)^2

The Attempt at a Solution



a)

ET=(0.5)(320 N/m)(0.10m)^2
ET= 1.6J

b)

1.6J=(0.5)(12kg)(V)^2 + (0.5)(320N/m)(0)
v=0.52m/s

c)

1.6J=(0.5)(12kg)(V)^2 +(0.5)(320N/m)(0.05m)^2
v=0.45m/s

Could someone verify this for me? Thanks
 
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Those look correct to me (the method, I did not check the numbers).
 
1.a) E=1/2KA^2=1/2(320N/m)(0.1m)^2=1.6J b) V(max)=wA
 
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