Calculate the velocity of the particle at t=4.0 s.

  • Thread starter Thread starter student000
  • Start date Start date
  • Tags Tags
    Particle Velocity
AI Thread Summary
To calculate the velocity of a 2.0 kg particle at t=4.0 s, the net force applied is given by F = 3t^2 - 12t. The acceleration can be determined using the formula a = F/m, leading to a = (3t^2 - 12t) / 2. The confusion arises regarding the mass value in the acceleration formula; it should be 2 kg, not 4. By integrating the acceleration over the time interval and adding it to the initial velocity of -6.0 m/s, the final velocity at t=4.0 s can be calculated.
student000
Messages
7
Reaction score
0
A 2.0 kg particle is moving along the x-axis to the left with a velocity of v= -6.0 m/s. Suddenly, between times t =0 and t = 4.0 x a net force = 3t^2 – 12t is applied to the particle, where F is in N and t is in s. Calculate the velocity of the particle at t=4.0 s.
I am having trouble making the numbers work. Thanks
 
Physics news on Phys.org


Well, what have you tried so far?
 


Someone told me to use this formula but I don't understand why the 4 is in the first equation because the mass is 2 kg
 


Sorry, the formula is
a= force/mass= (3t^2-12t)/4

Why is there a 4?
 
Thread 'Voltmeter readings for this circuit with switches'

Thread 'Voltmeter readings for this circuit with switches'

TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
View full post »
Thread 'Correct statement about a reservoir with an outlet pipe'

Thread 'Correct statement about a reservoir with an outlet pipe'

The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
View full post »

Similar threads

Find the value of ##T## and distance of particle in the first ##4## seconds
Replies
2
Views
970
Instantaneous Acceleration Given Equation for Velocity
Replies
7
Views
1K
How to calculate the average velocity?
Replies
13
Views
2K
Energy of particle in simple harmonic motion
Replies
13
Views
1K
Calculate Distance Traveled: Instantaneous vs. Average Velocity
Replies
5
Views
2K
Acceleration & max displacement from velocity equation
Replies
9
Views
5K
How Do You Calculate Instantaneous Velocity at a Midpoint in Particle Motion?
Replies
7
Views
3K
Solve Spring Force Problem: Displacement, Velocity & Acceleration
Replies
6
Views
2K
Finding the y-component of a velocity vector
Replies
2
Views
2K
What Angle Causes Particles A and B to Collide?
Replies
3
Views
3K

Hot Threads

Recent Insights

Back
Top