Calculate the water level in a pipe.

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collegekid
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This was a question on my last exam for physical chemistry. There were no examples in the book as to how to do this question and I think it pertains to physics. I would like to know how to do this in the event that it appears on the final.

"An iron pipe 2 m long and closed at one end is lowered vertically into water until the closed end is flush with the water surface. Calculate the height h of the water level in the pipe. Additional data: 25 degrees Celsius, diameter of pipe = 3 in, density of water is 1 x 10^3 kgm^-3, barometric pressure is 100,000 Pa = 10 hydrostatic head of water. Neglect the effect of water vapor pressure."

Thanks
 
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The level of the water inside the pipe will be such that the water pressure and air pressure at the interface are equal to each other.
 
Boyle's Law applies here: p1v1=p2v2

I am assuming barometric pressure is p1
p2 is calculated by hydrostatic pressure
p2=p1+density*g*height

v1 = pi*r2*h1 (convert units)
v2= p1v1/p2

h2=v1/(pi*r2)

I get 5.2 cm