(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 5.00 kg package slides 1.50 m down a ramp that is inclined at 12 degrees below horizontal. The coefficient of kinetic friction is 0.310.

a- Calculate the work done by friction.

b- Calculate the work done by gravity.

c- Determine the net work done on package.

d- If thepackage started sliding with a speed of 2.2 m/s, find the final speed.

2. Relevant equations

Fk = n * coefficient

W = Fd cos angle

K= i/2 mv^2

3. The attempt at a solution

a-

n (Normal) = wcos 12= 47.9 N

Fk (Friction) = normal * coefficient = 14.8N

Work Fk = 1.5m * 14.8 N * cos 180 = -22.2 J

b-

wsin12 * 1.5m * cos 0 = 15.3 J

c-

W total = 15.3J - 22.2 J = -6.9 J

d-

1/2 m v init ^2 - 6.9 J = 1/2 m vfinal ^2

12.1 J - 6.9 J = 2.5 kg v final ^2

v final = 1.44 m/s

I was feeling pretty good about this, but I showed it to someone in my school's math lab and he told me he thought it was all wrong. He said I need to break every force in x and y components. I don't see why I would. I would appreciate it if someone could tell me if I am doing this correctly.

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# Homework Help: Calculate the work done by friction of package

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