What is the work done by the two tugs pulling a tanker?

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Two tugs are pulling a tanker with forces of 1,400,000 N each, angled 14 degrees west and east of north, respectively, over a distance of 0.66 km. The initial calculation for work done was incorrect due to unit conversion errors, as the distance was mistakenly treated in meters instead of kilometers. The correct approach involves ensuring the distance is converted to meters for accurate calculations. The resultant force from both tugs was calculated as 2,716,828 N, leading to a work done calculation of approximately 1.79 million Nm. Attention to unit consistency is crucial for solving physics problems accurately.
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Homework Statement



Two tugs pull a tanker. Each at a force 1400000N with one at an angle 14degrees west of north, the other 14degrees east of north. They pull the tanker 0.66km north.

Homework Equations



W=Fs

The Attempt at a Solution



I simply took the vector force of 1 tanker

1400000Cos(14) = 1358414N multiplied it by two for both tugs = 2716828

Therefore W (asked in 3 sig figs) = 2716828*0.66 = 1.79*10^6Nm

Unfortunately I'm told this is wrong :frown:

Appreciate any help!
 
Last edited:
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You forgot the distance!
 
mjcowley said:

Homework Statement



Two tugs pull a tanker. Each at a force 1400000N with one at an angle 14degrees west of north, the other 14degrees east of north. They pull the tanker 0.66km north.

Homework Equations



W=Fs

The Attempt at a Solution



I simply took the vector force of 1 tanker

1400000Cos(14) = 1358414N multiplied it by two for both tugs = 2716828

Therefore W (asked in 3 sig figs) = 2716828*0.66 = 1.79*10^6Nm

Unfortunately I'm told this is wrong :frown:

Appreciate any help!


Look at your units.
 
Doc Al said:
You forgot the distance!
OK... you put in the distance (good!), but the distance is measured in km, not meters.
 
lylos said:
Look at your units.

Good ol MKS

Thanks for that :)
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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