- #1

://Justice

- 27

- 0

## Homework Statement

So, this is pretty easy and simple, I am just missing something obvious here I am pretty sure. This stems from a question I asked earlier tonight.

Calculate the time it took from launch to land, given a velocity of 30.197m/s, and a distance traveled of 85m. (other irrelevant data: Object was initially launched at 33 degrees. Refer to https://www.physicsforums.com/showthread.php?p=2890328#post2890328 for more info)

## Homework Equations

Perhaps, X=Xo+Vot+.5at^2 ?

## The Attempt at a Solution

So, I would use the formula X=Xo+Vot+.5at^2, correct? But then, I get a bit confused...

-.5t^2=Vot-X

divide by t

-.5t=Vo-X

t=-2(Vo-X)

but that is incorrect, I think... SO I dunno... Help, please... Thank you

Oh, wait... Am I maybe just way over-analyzing this? Would it be as simple as Distance/Velocity=Time? Therefore, V=30.197m/s , and D=85m, so 85/30.197=2.815s. But that seems a bit short. The empirical data is 4s (we must find the percent error), that is quite a large percent error...