Calculate Torque: Vector Products Homework

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The discussion revolves around calculating torque using the vector product for a pebble subjected to a force. The force is given as (8.7 N)i - (4.2 N)k, and the position vector is (3.7 m)j - (6.5 m)k. The user successfully solved part (a) but struggles with part (b), repeatedly arriving at an incorrect answer of 0i + 6.21j + 0k. There is confusion regarding the interpretation of the position vector and its relation to the pebble's location, particularly whether the pebble is at the origin. Clarification on these points is sought to resolve the issue with part (b).
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Homework Statement


Force = (8.7 N) - (4.2 N) acts on a pebble with position vector = (3.7 m) - (6.5 m), relative to the origin. What is the resulting torque acting on the pebble about (a) the origin and (b) a point with coordinates (5.0 m, 0, -1.7 m)?


Homework Equations


The cross product torque=rxf
r'=r-d


The Attempt at a Solution


I got part (a) correct, however I cannot get part (b) correct, I've done it about 5 times and it is completely wrong, my answers are: 0i + 6.21j + 0k. Can anyone tell me what I'm doing wrong?
 
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How did one do the first part?

I'm a bit confused as to the position vector (3.7 m) - (6.5 m) and the pebble location. Is the pebble at the origin and the position vector is the moment arm of the force?
 
Force is Force = (8.7 N)i - (4.2 N)k and position vector = (3.7 m)j - (6.5 m)k, which is relative to the origin
 
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