- #1
Anya91
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The flywheel of a steam engine begins to rotate from rest with a constant angular acceleration of 1.35 rad/s2. It accelerates for 33.9 s, then maintains a constant angular velocity. Calculate the total angle through which the wheel has turned 51.1 s after it begins rotating.
α = 1.35 rad/s^2
t1 = 33.9 s
t2 = 51.1
Δt = t2 - t1 = 17.2 s
θ = 1/2 * α^2 * t1 + ω * Δt
θ = 1/2 * α^2 * t1 + α*t1 * Δt
θ = α*t1 [1/2 * α + Δt]
θ = 1.35*33.9 [1/2 * 1.35 + 17.2]
θ = 81.8049375 rad
θ = 4687.77662 degree ~ 130.2 rotation
I got incorrect answer?? What's wrong with that??
Thank you
α = 1.35 rad/s^2
t1 = 33.9 s
t2 = 51.1
Δt = t2 - t1 = 17.2 s
θ = 1/2 * α^2 * t1 + ω * Δt
θ = 1/2 * α^2 * t1 + α*t1 * Δt
θ = α*t1 [1/2 * α + Δt]
θ = 1.35*33.9 [1/2 * 1.35 + 17.2]
θ = 81.8049375 rad
θ = 4687.77662 degree ~ 130.2 rotation
I got incorrect answer?? What's wrong with that??
Thank you
