Calculate Work Done by Ideal Gas

AI Thread Summary
The discussion focuses on calculating the work done by an ideal gas during a two-step process involving cooling and expansion. Initially, the gas is at 9 atm and 1 L, then cooled to 1 atm at constant volume before expanding to 7 L at constant pressure. The work done during the expansion is calculated using the formula W = PΔV, emphasizing the need to convert units from atm to Pa and liters to cubic meters. Participants confirm that the pressure and volume changes provide sufficient information to determine the total work done. The key takeaway is the importance of unit conversion in the calculation process.
notsam
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Homework Statement

1 mole of an ideal gas is at 9 atm pressure,
occupies 1 L and has an internal energy of
474 J. The gas is first cooled at constant
volume until its pressure is 1 atm. It is then
allowed to expand at constant pressure until
its volume is 7 L with an internal energy of
766 J.
Calculate the work done by the gas.
Answer in units of J.



Homework Equations

W=pv+p2v2



The Attempt at a Solution

So I'm thinking that the work will equal the preassure times the volume change plus the next preassure times the volume change to give me the total work in J. Yes?
 
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notsam said:

Homework Statement

1 mole of an ideal gas is at 9 atm pressure,
occupies 1 L and has an internal energy of
474 J. The gas is first cooled at constant
volume until its pressure is 1 atm. It is then
allowed to expand at constant pressure until
its volume is 7 L with an internal energy of
766 J.
Calculate the work done by the gas.
Answer in units of J.
Since the expansion is at constant pressure, W = P\Delta V. Be careful in converting units (atm. must be converted to Pa or N/m; litres to m^3). You are given the change in volume and the pressure so it should not be difficult.

AM
 
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