Calculated the pressure of the alcohol

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    Alcohol Pressure
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The discussion revolves around calculating the pressure inside a bubble of air located 4 meters below the surface of ethyl alcohol in a rigid container, where the air pressure above the liquid is 1.10 atm. The pressure at that depth was calculated to be approximately 1.3 X 10^5 Pa using the equation P = P(atm) + pgh, with the density of ethyl alcohol provided. Participants confirmed that the calculated pressure of 1.33 X 10^5 Pa appears correct. It was suggested that the pressure inside the bubble can be assumed to equal the pressure of the surrounding liquid, leading to the conclusion that the calculated pressure is indeed the answer needed. The discussion emphasizes the application of fluid pressure principles in a practical scenario.
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Homework Statement


Air is trapped above liquid ethyl alcohol in a rigid container. If the air pressure above the liquid is 1.10atm, determine the pressure inside a bubble 4.0m below the surface of the liquid.

Image: Think of a cylindrical container with a layer of air at the top. The remaining is filled with ethyl alcohol. 4m below the top of the alcohol is a bubble of air.

Homework Equations



P=P(atm)+pgh
p(ethyl-OH)=.806X10^3kg/m^3

The Attempt at a Solution



So i calculated the pressure of the alcohol 4m below the surface and got 1.3X10^5Pa. However, I'm not sure what to do in order to get the pressure in the bubble.
Suggestions would be appreciated.

thanks
 
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How did you go from a density of 0.8X10^3 to a pressure of 1.3X10^5? What units are all these quantities in?
 
This is what i did in order to get the pressure of the ethyl 4m down:

P=1.01310^5Pa+(.806X10^-3kg/m^3)(9.8m/s^s)(4m)=1.33X10^5Pa
 
Looks okay so far.

Now, since they don't tell you the size of the bubble, you are probably expected to assume that the pressure inside the bubble is equal to the pressure of the liquid around it. So you've got the answer you need.
 
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