Calculating a particles most probable speed

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The discussion focuses on calculating the most probable speed of diatomic carbon dioxide gas (CO2) at 281 Kelvin using the formula V_m_p = √(2*k_B*t/m). The participants clarify that the molar mass of 44.0 g/mol must be converted to kilograms for accurate calculations. It is emphasized that the mass used in the equation refers to the mass of an individual particle, not the mass per mole. After addressing these points, the correct approach to solving the problem is confirmed. The conversation concludes with a resolution to the calculation issue.
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[SOLVED] Calculating a particles most probable speed

Homework Statement



Diatomic carbon dioxide gas (CO2) has molar mass of 44.0 g/mol is at a temperature of 281 Kelvin.

Calculate the most probable speed .

Homework Equations



V_m_p = \sqrt{\frac{2*k_B*t}{m}}

The Attempt at a Solution



V_m_p = \sqrt{\frac{2*(1.3807*10^-^2^3)*281}{44}}

I have also tried with

V_m_p = \sqrt{\frac{2*(1.3807*10^-^2^3)*281}{0.044}}

with m in kg/mol, but to no avail. I am sure this is the right equation,

TFM
 
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The m stands for mass, not mass per mol!

Convert the 44g/mol to kg first.
 
It doesn't specify the number of moles, so is it the mass of an individual particle?

TFM
 
I've just checked and it is.

thanks Nick89 :smile:
 
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