Calculating Acceleration and Velocity in Newton's Third Law Scenario

In summary: Yes, this is correct. The velocity of the gun is in the opposite direction of the ball. Just like when you shoot a bullet, the bullet goes one way, and the gun goes in the other (the recoil).
  • #1
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Homework Statement


A paintball with a mass of 0.15 kg is fired from a paintball gun that has a mass of 5.5kg. The paintball leaves the gun with a velocity of 45 m/s [N] having accelerated for 0.10s. Calculate the acceleration and the final velocity of the paintball gun.
 
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  • #2
Here, you would use Newton's third law, and that the forces should equal. "For every action, there is an equal, but opposite reaction." The paintball gun forces the paintball in the +x direction, the ball pushes the gun in the -x direction. (this is why you feel recoil when shooting).

Find the force that's acting on the paintball.

Fball = mballaball

aball = (vf - vi)/t

This is all given to you in your question. simply solve for the Force. Since the total force must equal 0

Fball + Fgun = 0

Fball = - Fgun

Here, you can equate the force that's on the gun. Since you know the mass of the gun, you can find its acceleration. Then using the same equation as before,

agun = (vf - vi)/t

And just solve for the final velocity. (the initial should be zero as it starts from rest, before the gun is fired) (and the t value is the same as before. It's only accelerating as long as the ball enacts on the gun, so the time is 0.10s)
 
  • #3
Rawrr! said:
Here, you would use Newton's third law, and that the forces should equal. "For every action, there is an equal, but opposite reaction." The paintball gun forces the paintball in the +x direction, the ball pushes the gun in the -x direction. (this is why you feel recoil when shooting).

Find the force that's acting on the paintball.

Fball = mballaball

aball = (vf - vi)/t

This is all given to you in your question. simply solve for the Force. Since the total force must equal 0

Fball + Fgun = 0

Fball = - Fgun

Here, you can equate the force that's on the gun. Since you know the mass of the gun, you can find its acceleration. Then using the same equation as before,

agun = (vf - vi)/t

And just solve for the final velocity. (the initial should be zero as it starts from rest, before the gun is fired) (and the t value is the same as before. It's only accelerating as long as the ball enacts on the gun, so the time is 0.10s)

When calculating the acceleration of the ball would I use 0 as the final velocity?
 
  • #4
The final velocity would be the velocity it has when it leaves the barrel. So in your initial question, you say the ball leaves the gun with a velocity of 45 m/s . The initial velocity of the ball would be zero as both the gun and the ball are at rest, before the gun is shot.
 
  • #5
Rawrr! said:
The final velocity would be the velocity it has when it leaves the barrel. So in your initial question, you say the ball leaves the gun with a velocity of 45 m/s . The initial velocity of the ball would be zero as both the gun and the ball are at rest, before the gun is shot.

aball= Vf-Vi/t
= 45-0/0.10
= 450m/s^2

Fball=ma
=(0.15)(450)
=67.5 N

Fgun= -67.5N

Fnet=ma
-67.5=(5.5)(-a)
agun=12.27 m/s^2

agun=Vf-Vi/t
12.27 =Vf-0 / 0.10
Vf = 1.2 m/s

Is this correct?
 
  • #6
Looks correct! Just remember that the velocity of the gun is in the opposite direction of the ball. Just like when you shoot a bullet, the bullet goes one way, and the gun goes in the other (the recoil). (If it's going to be graded, it might be beneficial to write down the direction of the velocity, in case they look for that).
 

What is Newton's Third Law?

Newton's Third Law states that for every action, there is an equal and opposite reaction. This means that when one object exerts a force on another object, the second object will exert an equal force in the opposite direction.

What is an example of Newton's Third Law in action?

An example of Newton's Third Law in action is when a person jumps off a boat into the water. The person exerts a force on the boat in one direction, causing the boat to move in the opposite direction with an equal force.

How is Newton's Third Law relevant in everyday life?

Newton's Third Law is relevant in everyday life because it explains how forces interact with each other. It helps us understand why objects move and how they move in certain ways.

What are some common misconceptions about Newton's Third Law?

One common misconception about Newton's Third Law is that the forces have to cancel each other out, but this is not always the case. The forces can be equal in magnitude but still have different effects due to differences in mass and acceleration.

Another misconception is that the forces have to act on the same objects, but they can act on different objects as long as they are interacting with each other.

How does Newton's Third Law apply to space travel?

In space, there is no air resistance or friction, so objects will continue to move in a straight line unless acted upon by a force. Newton's Third Law explains how rockets are able to move in space by pushing hot gases in one direction, causing the rocket to move in the opposite direction with an equal force.

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