Calculating Acceleration and Velocity of a Falling Ball in One Dimension

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The discussion focuses on calculating the speed and acceleration of a ball dropped from a height of 3 meters that bounces back to 2 meters. The initial calculation for the speed upon hitting the ground is derived using the formula V^2 - V0^2 = 2gs, resulting in V = sqrt(60). However, there is a correction needed for the speed of the ball when it leaves the ground, as the constant acceleration formula cannot be applied over the bounce. The acceleration during the bounce is calculated as a = (10 - sqrt(60)) / 0.02, indicating an upward direction. The conversation highlights the importance of using appropriate formulas for varying conditions in motion.
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A ball is released from the height 3 meters and after it hits the floor it reaches the height 2 meter. A) Whats the speed of the ball in the moment when it meets the ground?
My answer : V^2-V0^2=2gs and here we find V=sqrt60.
What is the speed of the ball in the moment it leaves the ground? V2^2-V^2=2gh2 so V2^2- sqrt60=2g*2 and here we find V2=10
c) If the ball meets the ground for 0.02 seconds what's the direction and numerical value of the acceleration? The direction is upside down and a=(10-sqrt60)/0.02 ARE THESE CORRECT?
 
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Hi Elaia06! :smile:

(try using the X2 button just above the Reply box :wink:)
Elaia06 said:
A ball is released from the height 3 meters and after it hits the floor it reaches the height 2 meter. A) Whats the speed of the ball in the moment when it meets the ground?
My answer : V^2-V0^2=2gs and here we find V=sqrt60.

fine :smile:
What is the speed of the ball in the moment it leaves the ground? V2^2-V^2=2gh2 so V2^2- sqrt60=2g*2 and here we find V2=10

no, that's a constant acceleration formula, so you can't use it "over the bounce" …

try it with final speed 0 :wink:
 
You mean I should correct the third question,not the second one? maybe you did a little mistake over there?
 
no i did mean the second question (What is the speed of the ball in the moment it leaves the ground?)
 
I attached an image to the reply,it has the formulas for the non constant acceleration..but I don't have the time...
 

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