Calculating Acceleration On A Ramp

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To calculate the acceleration of a skateboarder on a 20-degree ramp, the net force acting on the system must be considered, including gravitational and frictional forces. The skateboarder's weight of 654 N has a component acting parallel to the ramp, which influences acceleration. The frictional force of 67 N opposes this motion, requiring adjustment in calculations. The correct approach involves using the net force equation, factoring in both the gravitational component and friction. Ultimately, the acceleration can be determined by applying Newton's second law, considering the effective forces acting on the skateboarder.
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A student is skateboarding down a ramp that is inclined 20 degrees with respect to the horizontal. The speed of the skateboarder at the top of the ramp is 3.0 m/s and the speed of the skateboarder at the bottom of the ramp is 7.6 m/s. The frictional force between the ramp and the skateboard is 67 N.

(a) If the combined weight of the student and the skateboard is 654 N, determine the acceleration of the student/skateboard system.

I've tried f=ma saying that
(654)-(67) = 654/9.8 [a]

Would that work?
 
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don't forget to take into account the fact that the student is moving parallel to the surface of the ramp, while his weight is directed straight down. This means that only the component of his weight that is parallel to the surface of the ramp is going to affect his acceleration in that direction.
 
Which component of his weight would be parallel? I would assume that the 654 N of the combined weight would be?
 
"weight" is the force that a person (or object) feels due to gravity. Since gravity is always directed straight down, the force, and thus the weight, is directed straight down.
 

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