Calculating Acceleration with Friction and Applied Force

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To calculate the acceleration of a sled and cargo weighing 490 N towed by a tractor with a force of 300 N over a surface with a coefficient of friction of 0.400, the normal force is determined to be 490 N. The frictional force is calculated using the equation fk = μkN, resulting in a frictional force of 196 N. The net force acting on the sled is then found by subtracting the frictional force from the applied force. The mass is converted from weight to kilograms by dividing by 9.81, yielding approximately 49.95 kg. Finally, the acceleration is calculated using the formula a = (F - fk)/m, leading to the solution.
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Homework Statement



A sled and cargo weighing 490 N is towed by a tractor over a horizontal field where the coefficient of sliding friction is 0.400. If the tractor exerts a force of 300 N, what is the acceleration of the sled?

Homework Equations


Fk/µkM


The Attempt at a Solution


i Tried changing the 490N to Kg by dividing it by 9.81. that gave me 49.95. i then multiplied that by 0.400. then i divided that final number from 300 N.
 
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dance_sg said:

Homework Statement



A sled and cargo weighing 490 N is towed by a tractor over a horizontal field where the coefficient of sliding friction is 0.400. If the tractor exerts a force of 300 N, what is the acceleration of the sled?

Homework Equations


Fk/µkM


The Attempt at a Solution


i Tried changing the 490N to Kg by dividing it by 9.81. that gave me 49.95. i then multiplied that by 0.400. then i divided that final number from 300 N.

490 N is the normal reaction. So the frictional force fk= μkN.
Acceleration = (F - fk)/m
 
O thank you so much :)
 
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