Calculating Angles for Many Electron System w/ L=2, S=1, J=2

  • Thread starter Thread starter neelakash
  • Start date Start date
  • Tags Tags
    Spectroscopy
neelakash
Messages
491
Reaction score
1

Homework Statement



For a many electron system with L=2,S=1 and J=2 calculate the angle between the L and S vectors both according to the old quantum theory and quantum mechanics.

Homework Equations



The Attempt at a Solution



I suppose this problem is nothing but a simple application of cosine rule.The external angle is the answer.
But I am thinking twice as they mention: both according to the old quantum theory and quantum mechanics.

Am I missing something?
 
Physics news on Phys.org
In the Bohr model (I think that qualifies as "old quantum theory"), we have L=n\hbar, where n=1,2,3,.... Contrast that with modern quantum mechanics.

Does that help?
 
neelakash said:

Homework Statement



For a many electron system with L=2,S=1 and J=2 calculate the angle between the L and S vectors both according to the old quantum theory and quantum mechanics.
In QM, use LS cos(theta)=L.S=[J(J+1)-L(L+1)-S(S+1)]/2.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top