Calculating Angular Momentum: Mass, Radius, and Frequency Considerations

AI Thread Summary
To calculate angular momentum for a spinning turntable with a mass of 4.96 kg and a radius of 0.092 m at a frequency of 0.53 rev/s, the moment of inertia (I) is calculated using the formula I = (1/2)(mr^2). The angular momentum (L) is then determined using L = I(ω), where ω must be converted from revolutions per second to radians per second by multiplying by 2π. The initial calculation resulted in 0.011 (kgm^2)/s, but the correct angular momentum is 0.0699 (kgm^2)/s. The error was due to not converting the frequency into the correct units for angular velocity.
jmb07
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A turntable has mass 4.96 kg and a radius of 0.092 m and is spinning with a frequency of 0.53 rev/s. What is the angular momentum??

As simple as this problem seems, I just cannot seem to get the correct answer...here is what i have so far:

I (for a disc) = (1/2)(mr^2)
L = I(omega)
I also know that angular momentum = frequency x I

So,
0.53rev/s(.5 x 4.96kg x 0.092^2) = 0.011 (kgm^2)/s
However the correct answer is 0.0699...what am i doing wrong?
 
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jmb07 said:
L = I(omega)
I also know that angular momentum = frequency x I
L = Iω, where ω is in radians/sec.

So,
0.53rev/s(.5 x 4.96kg x 0.092^2) = 0.011 (kgm^2)/s
However the correct answer is 0.0699...what am i doing wrong?
Convert to proper units.
 
The frequency is in revolutions per second; you need to convert it into radians per second. The conversion factor is 2\pi\ \text{radians} = 1\ \text{revolution}.
 
thanks!
 
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