Calculating Angular Velocity of a Shell Exiting a Barrel | Physics Homework

AI Thread Summary
To calculate the angular velocity of a shell exiting a barrel, the initial velocity is given as 320 m/s, with the shell making 2 turns in a barrel length of 2.0 m. The relevant equations for linear and angular motion are provided, including vf = vi + at and vf^2 - vi^2 = 2ax. The discussion emphasizes the need to determine the time taken for the shell to complete the 2 turns, denoted as ts, to find the angular velocity. The angular velocity can be expressed in terms of ts, and the conversion from turns to radians is also noted, as 2 turns equal 4π radians. The final angular velocity is calculated to be 2.0 x 10^3 rad/s.
paragchitnis
Messages
25
Reaction score
0

Homework Statement


A shell acquires the initial velocity v = 320m/s, having made n = 2.0 turns inside the barrel whose length is equal to l = 2.0m. Assuming that the shell moves inside the barrel with uniform acceleration, find the angular velocity of its axial rotation at the moment when the shell escapes the barrel.

Homework Equations


vf = vi + at
This equation can be used for linear as well as angular velocity
x = vit + at^2
vf^2 - vi^2 = 2ax

The Attempt at a Solution


The given answer is 2pi nv/l = 2.0 x 103 rad./s
 
Last edited:
Physics news on Phys.org
How much time it took to make those n = 2 turns? then if you know this time, can you find angular velocity?
 
housemartin said:
How much time it took to make those n = 2 turns? then if you know this time, can you find angular velocity?

Time is not given. But let us consider it take ts for n = 2 turns. can we get the answer in terms of t?
 
Time is what you have to find, you know final ant initial linear velocities and the length of the barrel, from here you can find ts. Angular velocity is measured in radians per second. And two rotations is how much radians? And you when you find time it took to make those two rotations, then...? ;]
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top