Calculating approx. Values in km3, m3, cubic miles, and gallons

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Homework Help Overview

The problem involves calculating the approximate volume of Earth's oceans based on its radius, surface area, and average depth of water. The subject area includes geometry and volume calculations related to spheres and fluid dynamics.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss methods for calculating the volume by first determining the surface area of the Earth and then applying the average depth of water. Some suggest a straightforward approach using the formula for the surface area of a sphere, while others consider subtracting non-water portions from the total volume of the Earth.

Discussion Status

The discussion is active, with participants sharing different methods and perspectives. Some guidance has been offered regarding the calculation steps, but there is no explicit consensus on the best approach yet.

Contextual Notes

Participants are navigating the complexity of unit conversions and the implications of using different methods for calculating volume. There is mention of confusion regarding integration and the need for clarity in the approach.

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Homework Statement


Earth’s radius is 6370 km and approximately 70% of
its surface is covered with water, to an average depth
of 12,000 feet. Calculate the approximate volume, in
km
3
, m
3
, cubic miles and gallons of Earth’s oceans.


Homework Equations





The Attempt at a Solution




I was told to find the area and to multiply by the avrg depth but i am still confused.
 
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Welcome to PF.
You can calculate the total volume of the Earth and then subtract the non water portions.
1. Calculate total volume in desired unit.
2. Calculate volume of "inner" portion.
3. Subtract inner portion from total volume then multiply by 0.7 to account for 70% water coverage.
 
Isn't it a lot easier than that?

Just calculate the surface area of the sphere (4 * Pi * R2).
Multiply by 70/100 to get the area covered by water.
Multiply by the average depth.

Obviously convert everything to appropriate units first. For example if you convert the average depth to km the answer will be in km3.

Then convert to the other units required.
 
Yes your method is easier. I just couldn't get away from integration in my head so I pieced it out for the OP in not quite as eloquent manner as you did...
 

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