Calculating Average Acceleration of a Bouncing Super Ball

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To calculate the average acceleration of a Super Ball bouncing off a wall, the initial velocity is 30.0 m/s, and the final velocity after rebounding is 20.5 m/s. The ball is in contact with the wall for 3.70 ms, which is 0.0037 seconds. The average acceleration can be determined using the formula: (final velocity - initial velocity) / time. The resulting calculation yields an average acceleration of 13600 m/s squared, despite confusion about the sign due to the ball's change in speed. Understanding the direction of velocity change is crucial in interpreting the acceleration value correctly.
MG5
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A 45.0-g Super Ball traveling at 30.0 m/s bounces off a brick wall and rebounds at 20.5 m/s. A high-speed camera records this event. If the ball is in contact with the wall for 3.70 ms, what is the magnitude of the average acceleration of the ball during this time interval?

Apparently the answer is 13600 m/s squared.

No idea how to get that though.
 
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MG5 said:
A 45.0-g Super Ball traveling at 30.0 m/s bounces off a brick wall and rebounds at 20.5 m/s. A high-speed camera records this event. If the ball is in contact with the wall for 3.70 ms, what is the magnitude of the average acceleration of the ball during this time interval?

Apparently the answer is 13600 m/s squared.

No idea how to get that though.

I'm a bit sleepy at the moment and might have overlooked something, but it doesn't make sense that the acceleration is positive when the ball slows down by 9,5m/s..
 
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