Calculating Average Temperature Using Integrals

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A certain city, the temp in degrees Farenheit, t hrs after 9 am was modeled by the function: T(t)=50 + 14 sin (Pi t / 12)
Find avg temp during the period from 9 am to 9 pm.

What i did was take the Int[50 + 14 sin (Pi t / 12),t,0,9]... but this doesn't produce the answer. It says model after 9 am so at 9=0 for a , b = 10 for 9pm?
Any help?
 
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shouldnt b be 12 and not 10 since it is 12 hours from 9am - 9pm
 
Set your limits a,b to a = 9 and b = 21 (using 24-hr notation)
 
i tried 9 to 21 and it didnt work before...
 
it works from 0 to 12, thanks, don't know why i thought 10 DUH
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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