Calculating Charge Needed for Same Binding Energy in H2+

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To achieve the same binding energy in the H2+ molecular ion, a negative charge must be placed halfway between the two protons, which are 0.106 nm apart with a binding energy of 2.65 eV. The negative charge is necessary to counteract the electrostatic repulsion between the protons, stabilizing the system. The binding energy is defined in terms of the three-charge system: two protons and one negative charge. Calculations should focus on the electrostatic forces without considering other nuclear forces. Providing detailed calculations will enhance understanding and accuracy.
ghallya
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hi I need help in solving this

The protons the H2+ molculer ion are 0.106 nm apart and the binding energy of H2+ is 2.65 ev , what negetive charge must be placed halfway between two protons this distance apart to give the same binding energy?

I calculated it for the electrons , but here i didn know for the protons ?
I tryed to use the graph I had but I don't think its the right solution
so if someone could help me or give an equation I could apply

thanx
 
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Please correct me if I'm wrong...

The two protons repel each other so left to itself, the two proton system is electrostatically unstable. You need a negative charge somewhere between them so that they are both attracted to the -ve charge and effectively stay in place. The binding energy is now defined in terms of the 3 charge system: 2 protons + 1 negative charge. [No other nuclear force is being considered for the mathematical calculations]

Does this help?

PS--Show your work
 

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