Calculating Cp for Ideal Gases using Thermodynamic Relationships

AI Thread Summary
According to Meyer's formula, the calculated value of Cp for the ideal gas should be 13.314, but this option is not available. The discussion highlights an alternative method of calculating Cp by determining the Adiabatic Coefficient. It is confirmed that the relationship Cp = Cv + R holds true only for ideal gases. The volume for one mole of gas at normal temperature and pressure is consistent for both ideal and real gases. The conversation emphasizes the importance of using the speed of sound to find the adiabatic coefficient and subsequently calculate Cp.
Rongeet Banerjee
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Homework Statement
Is Meyers equation :
Cp - Cv =R always valid?
Relevant Equations
Cp=Cv +R
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In this particular Question according to Meyer's formula,the value of Cp should be (8.314+5) i.e. 13.314 .But that option is missing.
There is another approach to this problem by finding the Adiabatic Coefficient and then finding Cp.I have no problem with that approach.
But my initial doubt still remains.
 
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Rongeet Banerjee said:
Homework Statement:: Is Meyers equation :
Cp - Cv =R always valid?
Relevant Equations:: Cp=Cv +R

View attachment 264333
In this particular Question according to Meyer's formula,the value of Cp should be (8.314+5) i.e. 13.314 .But that option is missing.
There is another approach to this problem by finding the Adiabatic Coefficient and then finding Cp.I have no problem with that approach.
But my initial doubt still remains.
Cp = Cv + R is true only for an ideal gas. However, the volume occupied by one mole of gas at a certain temperature and pressure (NTP in this case) is the same for ideal and real gases. I think you are expected to determine ##\gamma## from the speed of sound and determine Cp from that.

AM
 
Thanks
 
Just to provide some justification: For any gas, you have ##C_V = \left(\frac{\partial U}{\partial T} \right)_V## and ##C_p = \left(\frac{\partial H}{\partial T} \right)_p##. Now $$H = U + pV \implies \left(\frac{\partial H}{\partial T} \right)_p = \left(\frac{\partial U}{\partial T} \right)_p + p \left(\frac{\partial V}{\partial T} \right)_p$$For an ideal gas, you have ##C_V = \left(\frac{\partial U}{\partial T} \right)_V = \left(\frac{\partial U}{\partial T} \right)_p##. Furthermore for an ideal gas, ##V = \frac{nRT}{p} \implies p \left(\frac{\partial V}{\partial T} \right)_p = nR##. Hence we finally obtain $$C_p = C_V + nR$$
 
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