Calculating Current Density and Current in a Gold Wire

AI Thread Summary
The discussion revolves around calculating current density and current in a gold wire, given the electron drift speed of 3.0 * 10^-4 m/s and a wire diameter of 0.50 mm. Participants emphasize the need for relevant equations, specifically mentioning I = nqv_dA for current and J = I/A for current density, where n represents the number of charge carriers. There is frustration expressed over the lack of clarity in the textbook and a request for more detailed guidance rather than simply referring back to the book. The importance of understanding the underlying concepts and equations is highlighted, as participants seek to clarify how to derive the necessary values for n and q. Overall, the thread underscores the challenges faced in applying theoretical knowledge to practical calculations in physics.
kyang002
Messages
22
Reaction score
0
The electron drift speed in a gold wire is 3.0 * 10^-4.

1. What is the current density in the wire?

2. What is the current if the wire diameter is 0.50 mm?

I am unsure of which equation to use.
Q = I delta t ??

Can someone help me out?
 
Physics news on Phys.org
kyang002 said:
The electron drift speed in a gold wire is 3.0 * 10^-4.

1. What is the current density in the wire?

2. What is the current if the wire diameter is 0.50 mm?

I am unsure of which equation to use.
Q = I delta t ??

Can someone help me out?[/QUOTE]

Look in your book,, there should be some equations relating current to drift velocity and current density.
 
Q = I delta t is the equation that I found. It doesn't make sense to me. Obviously I already looked in the book and cannot figure it out, that is why I am posting on this forum. If you can please leave more helpful info on how to solve the problem instead of telling me to look in the book, that would be much better.
 
Don't they give you the "n" for gold??You know what "n" stands for,right??U had to compute it at one of the other problems...

Daniel.
 
kyang002 said:
Q = I delta t is the equation that I found. It doesn't make sense to me. Obviously I already looked in the book and cannot figure it out, that is why I am posting on this forum. If you can please leave more helpful info on how to solve the problem instead of telling me to look in the book, that would be much better.

I highly doubt that these equations are not given in your book, and it doesn't do you much good to just plug in numbers without knowing what these equations mean, but I'll list them here just in case there was a disaster at the publishing company, and they left these out. You should try to find these in your book later, and see where they come from :smile: .

I \ = \ nqv_dA

J \ = \ \frac{I}{A} \ = \ nqv_d

where J is current density, n is number of free moving charge particles per unit volume, v_d is drift velocity, and A is cross sectional area.
 
I never figured it out because I was stuck on how to figure out n and q.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top