Calculating current in parallel wire

AI Thread Summary
The discussion focuses on calculating the current in a second parallel wire influenced by a first wire carrying 14.9A. The attractive force per unit length between the wires is given as 8.50×10^-4 N/m, and the distance between them is 6.20 cm. Participants highlight the importance of correctly applying the formula I2=(F/ΔL)(2πr/μ0I1) and checking arithmetic to avoid errors. One user suggests that incorrect exponent handling may lead to unreasonable results. The conversation emphasizes the need for careful calculations and verification before seeking assistance.
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Homework Statement



A vertical straight wire carrying an upward 14.9A current exerts an attractive force per unit length of 8.50×10-4N/m on a second parallel wire 6.20cm away. What is the magnitude of the current that flows in the second wire?

Homework Equations



I2=2pir*F/I1*4pi e-7

The Attempt at a Solution



I2=2pi(.062)*8.5e-4/14.9*4pi e-7
I2=2.7926e-11

I keep getting ridiculous numbers and I can't figure out what I'm doing wrong...help?!
 
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I think you got your equation slightly off.
Starting with F/\DeltaL=\mu0I1I2/2pi*r, I ended up with
I2=(F/\DeltaL)(2pi*r/\mu0I1).
 
Check your own arithmetic. The exponents indicate you screwed up the division.

Do the basic checks before running for help.
 

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