Calculating Cyclist Speed: 10 Secs and 5 Secs

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The cyclist's average speed is 1.8 m/s, with a top speed of 3.6 m/s reached in 10 seconds. To determine the distance covered in the last 5 seconds, one can use the formula for distance based on average speed. The discussion suggests that if the top speed is double the average speed, the cyclist likely started from rest, indicating a constant acceleration model. The total distance covered in the first 10 seconds can be calculated as the area of a triangle under the velocity vs. time graph. Understanding these calculations allows for estimating the cyclist's performance over the last segment of the race.
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The cyclist got a average speed of 1,8m/s and a top speed of 3,6sek
The time is 10 sek.
How do I get to know how long will the cyclist cycle the last 5 sek of the 10 sek. Can i conclude that with my formula?

Please help me
 
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If you mean that the top speed is 2 times the average speed, then
(in first approximation of constant acceleration) the lowest speed was zero.
So the graph of velocity vs time is through the origin, straight-line.

How far did he go in the whole 10 seconds? (½ vmax tmax)
this is the area of the triangle "under the curve" v vs t .

How far would he go, in the last half of the race?
(OK, what would his average speed be during this half?)
 

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