Calculating Density of Unknown Liquid: Problem and Solution

  • Thread starter Thread starter DoubleHelix
  • Start date Start date
  • Tags Tags
    Density
AI Thread Summary
To calculate the density of an unknown liquid, the mass of the water in the bottle was determined to be 20.0g by subtracting the empty weight from the full weight. The volume of the bottle was calculated to be 0.02 m³, leading to an initial density calculation of 1200 kg/m³. However, it was pointed out that the mass should be converted to kilograms for consistency in units, which affects the volume calculation. The discussion emphasized the importance of using SI units for accuracy and clarity, recommending density be expressed in kg/m³ rather than kg/L or g/mL. Accurate unit conversion is crucial to avoid significant errors in calculations.
DoubleHelix
Messages
15
Reaction score
0
Hi, here's my problem:

The balance of a bottle when empty is 70.0g, when full of water is 90.0g and when full of another liquid is 94.0g. The density of water is 1000km/m(to the power of 3), what is the density of the toher liquid?

I know that density = mass / volume so i think that i should take 70.0 away from 90.0 to get the mass of the water alone, so I get 20.0g. From here I'm stuck. Thanks for any help!
 
Physics news on Phys.org
You know that from the formula of density=mass/ volume.
You have mass of water and density of water. You can calculate the volume of the bottle that way. I'm sure you can take it from there.
 
Ah yes, so I need to calculate the volume of the bottle.

I found the volume of the bottle to be 0.02 and thus got the density to be = 24.0 / 0.02 = 1200kg m^3. Could you please clarify that i have done this correctly?
 
should density be shown in kg/l or g/ml
 
That answer is accurate. Very good. However I have to point out an error you have made. You did not convert your mass into kg, hence your volume is actually wrong since your density is in kg/m^3 while your mass cancels out. Make sure all your units are continous.

Addtionally, try to have a bearing of the quantities you calculate. 0.02 m^3 is very large, 20 litres, compared to the meagre 90 g of water.

Finally, density in kg/l is valid, however I strongly recommend you use kg/m^3 since that will make both of them SI units. For future questions, converting the units into SI can help you avoid many mistakes.:cool:
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top