Calculating Distance and Time in a Chasing Scenario

[swathi]

GRADE 11 physics PLEASE HELP ! =]

A student is late for school.
She runs out the door and starts down the street at 8.0 km/h.
Three minutes later, her mom notices that she left a book
she runs after her daughter at 12.0 km/h

a, how far did she get in three minutes?
b, how long did it take her mom to catch her?
c, how far away from home does her mom catch her?

um..
given info

DAUGHTER : 8.0 km/h
MOM : 12.0 km/h ... 3 minutes later..


any help would be appreciated..
even if you don't solve..
i just need to start..
sorry i haven't shown any work..
im lost !
thanks ! =]

 

[_Mayday_]

If this is homework, I would suggest moving it to the homework section of the site. Though I might as well give you a hint. You have to use this equation and be able to rearrange it.



$$Speed=\frac{Distance}{Time}$$

 

[dst]

Model mother and daughter as 0 dimensional particles in a vacuum...

It should be a simple case of speed = distance * time, i.e. 8km/h = distance traveled / time taken.

 

[_Mayday_]

A student is late for school.
She runs out the door and starts down the street at 8.0 km/h.
Three minutes later, her mom notices that she left a book
she runs after her daughter at 12.0 km/h

a, how far did she get in three minutes?
b, how long did it take her mom to catch her?
c, how far away from home does her mom catch her?

um..
given info

DAUGHTER : 8.0 km/h
MOM : 12.0 km/h ... 3 minutes later..


any help would be appreciated..
even if you don't solve..
i just need to start..
sorry i haven't shown any work..
im lost !
thanks ! =]

I will reaarange the equations for you, and let you plug in the values.

A) $$Distance = Speed \times Time$$

B) Here you are looking at when the mom's distance is equal to the daughters, so the mom's distance should equal the answer to the previous question.

$$Time = \frac{Distance}{Speed}$$

C) Here you are looking at the point in which the moms distance is equal to the daughters.

 

[swathi]

THANKS !
i got it =]