Calculating Distance of Two Speakers Producing 162Hz Sound

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To calculate the distance to the further speaker producing a 162Hz sound, the wavelength is determined to be approximately 2.13m using the speed of sound at 345m/s. The formula d(1) - d(2) / wavelength = phase difference / 2π is applied, where the phase difference for an intensity minimum is nπ. The calculation suggests that the distance to the further speaker is 4.09m, but this is incorrect as the phase difference should be considered as nπ rather than 2nπ. The correct approach requires adjusting the phase difference to reflect the conditions for an intensity minimum. Accurate calculations are essential for determining the correct distance to the further speaker.
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Two speakers produce a 162Hz sound in phase. If an intensity minimum is located 3.75m from the nearer speaker, find the distance to the further speaker if the speed of sound in the air is 345m/s.

Would it go like this
d(1)-d(2)/wavelength=phase difference/2pi
x-3.75/2.13=1/2pi
x=4.09m

This doesn't seem quite right let me know what to do please.
 
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lilkrazyrae said:
Two speakers produce a 162Hz sound in phase. If an intensity minimum is located 3.75m from the nearer speaker, find the distance to the further speaker if the speed of sound in the air is 345m/s.
Would it go like this
d(1)-d(2)/wavelength=phase difference/2pi
x-3.75/2.13=1/2pi
x=4.09m
This doesn't seem quite right let me know what to do please.
The difference in distance must equal a multiple of half a wavelength for a minimum (phase difference = n\pi not 2n\pi).

AM
 

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