Calculating Drop Time from 105m in a Helicopter

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To calculate the drop time of a box dropped from a helicopter at 105m with an upward speed of 5.50m/s, the initial height (xi) is 105m, and the initial velocity (vi) is 5.50m/s. The acceleration due to gravity (a) is -9.80m/s², as it acts downward. The correct equation to use is xf = xi + vit + 0.5at², where xf is the final height (0m when it reaches the ground). The discussion clarifies that the initial height is 105m and the initial velocity is indeed 5.50m/s, confirming the setup for the calculation.
marsh
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I need some help with a question please.
If a helicopter has a speed of 5.50m/s moving upward vertically and when at the height of 105m above Earth a box is dropped from the window how much time will it take to reach the ground?
 
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the problem is that i don't know what equation to use for this problem. Would the speed of the helicopter, 5.50m/s, be the speed of the package as well?
 
do i use xf=xi+vit+.5at^2 ?
 
x= xi+ vit+ (1/2)at2

where xi is the initial height, vi is the initial velocity and a is the acceleration due to gravity. Do you know what the initial height and velocity are for the package?

My answer to your question, which you posted while I was typing, is "yes"!
 
so the xi= om xf=105m and vi=5.50m/s vf= 0m/s a= 9.80m/s^2
 
is that correct?

or is the xf= 0m and xi=105m b/c it's being dropped from the top?
 
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