Calculating Electron Probability in a Cone

AI Thread Summary
The discussion centers on calculating the probability of finding an electron in a specific quantum state within a cone defined by a half-angle of 41 degrees about the z-axis. The user attempts to use the probability formula P=∫∫∫R(r)^2 * Y[θ,phi]^2 but expresses uncertainty in their approach, particularly regarding the radial wavefunction R(r). They derive the spherical harmonic Y(θ,φ) for the given quantum numbers but note that their integration results are incorrect. Other participants suggest verifying the radial wavefunction and ensuring the complex conjugate is considered in calculations. The conversation highlights the importance of correctly applying quantum mechanical principles in probability calculations.
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Homework Statement



Consider an electron in the n = 5, ℓ = 2, mℓ = -1 state.
What is the probability that the electron is located in a cone
of half angle 41◦ about the z axis? (In other words, what is the
probability that θ ≤ 41◦
?)

Homework Equations



P=∫∫∫R(r)^2 * Y[θ,phi]^2


The Attempt at a Solution



I'm not quite sure what I'm doing here, but this is as far as I got:

I said R(r) is a constant because the angle doesn't depend on the radius.

Next I found an expression for Y(theta,phi) from my textbook based on l and m_l:

Y(θ,f)=.5*sqrt(15/2pi)SinθCosθ * e^-i*f

I integrated Y^2, .7156<θ<pi, 0<f<pi

This probability is not right.

ANy ideas?
 
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You have assumed the radial wavefunction is a constant for that state... did you check, say, by looking it up or computing it? Did you remember to take the complex conjugate for the complex parts of the wavefunction?
 
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