Calculating Energy of Radiation in Proton-Antiproton Annihilation

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In summary, in proton-antiproton annihilation, a proton and an antiproton collide and disappear, producing electromagnetic radiation. The total energy of the radiation can be calculated using the equation E=mc2, where m is the mass of each particle (1.67*10-27) and c is the speed of light (2.998*108). The result is 3.002*10-10 joules or 1.87GeV. This method is correct, but it is possible that the number of marks for the question is a misprint.
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ProPatto16
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Homework Statement


in proton-antiproton annihilation a proton and an antiproton collide and disappear producing electromagnetiv radiation. if each particle has a mass of 1.67*10-27 and they are at rest just before collision, find total energy of radiation and give answer in joules and electron volts.


Homework Equations


rest energy, E=mc2


The Attempt at a Solution



E = [1.67*10-27 x (2.998*108)2] x 2

= 3.002*10-10 J

= 1.87GeV

is that right? the question is for 10 marks and it just seems to easy??
 
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  • #2
Your method is correct as far as I can tell. Two photons would have to be produced to conserve momentum but the question does ask for the total energy.

Perhaps the number of marks is a misprint.
 

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