Calculating Energy Stored in Series and Parallel Capacitor Circuits

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To calculate the energy stored in capacitor circuits with a 10-volt battery, one circuit has capacitors in series (5.3 µF and 2.4 µF) while the other has them in parallel. For series capacitors, the charge is the same across each capacitor, and the equivalent capacitance can be calculated using the formula 1/C_eq = 1/C1 + 1/C2. In contrast, for parallel capacitors, the total charge is the sum of the charges on each capacitor, and the equivalent capacitance is C_eq = C1 + C2. The energy stored in each configuration can be determined using the equation energy = (Q^2)/(2C), where Q is the charge on the capacitors. Understanding the differences in charge distribution between series and parallel configurations is crucial for accurate calculations.
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Homework Statement


you have a 10 volt battery and two separate circuits with capacitors. One circuit has the capacitors in series, the other has the capacitors in parallel. Find the energy stored

one capacitor is 5.3 microfarads
the other capacitor is 2.4 microfarads

Homework Equations


energy = (Q^2)/(2C)


The Attempt at a Solution


after finding the equivalent capacitance, would you just add the total amount of charge stored on each capacitor to find charge?
 
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tough to say without the picture...

if two capacitors are in series, then each capacitor has the same charge... and the equivalent capacitor has that same charge...

if two capacitors are in parallel, then the charge on the equiv. capacitance is the sum of the charges on each capacitor.
 
learningphysics said:
tough to say without the picture...

if two capacitors are in series, then each capacitor has the same charge... and the equivalent capacitor has that same charge...

if two capacitors are in parallel, then the charge on the equiv. capacitance is the sum of the charges on each capacitor.

so for the series capacitor, which holds the same amt charge on each capacitor, you wouldn't add the two charges on each capacitor together to get Q?
 
boogiebear said:
so for the series capacitor, which holds the same amt charge on each capacitor, you wouldn't add the two charges on each capacitor together to get Q?

no. the total charge is the same as the charge on each capacitor. have a look at this:

http://www.ac.wwu.edu/~vawter/PhysicsNet/Topics/Capacitors/ParSeriesCap.html
 
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