Calculating Force Applied to Box with Friction Coefficient \mu

[Angello90]

Hi guys,

I got this thought in my head.

If I have a box of mass x, being pulled towards East and the angle $$\theta$$,
then force applied to the box in order to move it on the surface with friction coefficient $$\mu$$ has to be in such a way:

My question is... wouldn't N be:

Or, N would be as usual W but in opposite direction? The drawing shows all the forces on the box:

Cheers and thanks for the thought

 

[Doc Al]

My question is... wouldn't N be:

You got it.

Or, N would be as usual W but in opposite direction?

Nope. You were right the first time. The key is that there must be no net force on the box in the vertical direction.

 

[Angello90]

Ok thanks a mil! I was bit confused