Calculating Force on a Sphere with 1 Bar Pressure

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Discussion Overview

The discussion revolves around calculating the force exerted on a sphere by pneumatic pressure, specifically in the context of a pneumatic air rifle and the acceleration of an airsoft BB. The focus is on the correct area to use for pressure calculations and the implications for force determination.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant seeks to calculate the force on a 6mm diameter projectile using a pressure difference of 1 bar, initially proposing to use the surface area of a hemisphere.
  • Another participant challenges this approach, stating that the correct area to use for pressure calculations is the cross-sectional area of the projectile, not the hemisphere.
  • A later reply clarifies that while the force acts perpendicular to the surface, using the hemisphere's area would require considering only the component of force along the barrel, ultimately leading back to the cross-sectional area for simplicity.

Areas of Agreement / Disagreement

Participants express disagreement regarding the appropriate area to use for calculating the force, with some advocating for the cross-sectional area while others initially consider the hemisphere's area. The discussion remains unresolved on the best approach.

Contextual Notes

There are limitations in the assumptions regarding the geometry of the projectile and the interpretation of pressure application, which may affect the calculations. The discussion does not resolve these assumptions.

cheekibreeki
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Hey people, first post, I'm sorry if I'm posting this in the wrong place.

How do you calculate the force exerted on a sphere? I'm building a pneumatic air rifle, and I'm trying to figure out how fast an airsoft bb accellerates with a certain pressure.

The projectile is 6mm in diameter, so that makes the surface on which the air pressure works 1/2 * (4 * pi * 3^2) = 1/2 * 113.1 = 56.5 mm^2 = 5.65 * 10^ -5 m^2.

What is the force on the projectile if the difference in pressure is 1 bar?
 
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cheekibreeki said:
surface on which the air pressure works 1/2 * (4 * pi * 3^2) = 1/2 * 113.1 = 56.5 mm^2 = 5.65 * 10^ -5 m^2.
It's an attractive notion to use the area of the hemisphere, an it's also incorrect. The area on which the pressure acts is the cross-sectional area of the projectile, period. Force then is pressure times area of the bore.
 
Thanks, that makes things a whole lot easier!
 
Just in case you're curious:
The force from the pressure acts perpendicular to the surface, so if you were to use the surface area of the hemisphere, you would have to use only the component of force that acts along the barrel. If you do the math it reduces to using the cross-sectional area.
 

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