Calculating Force on the Bottom of a Cylinder in Fluid Physics

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To calculate the force acting on the bottom of a cylinder filled with falling water, both static and dynamic pressures must be considered. The static pressure is determined by the height of the water column, while the dynamic pressure accounts for the velocity of the water as it enters the cylinder. The total pressure exerted on the bottom is the sum of static and dynamic pressures, leading to the conclusion that the force does not depend on the time or water consumption. The calculations confirm that the total pressure is equal to the product of density, gravitational acceleration, and the height of the water. This approach ensures an accurate representation of the forces at play in fluid dynamics.
Yegor
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I have the next problem:
Water is falling from the H=1 m into the cylinder.
Diametr of the culinder d=20 cm
Q=dV/dt=100 (cm^3)/s (consumption of the water).
I have to calculate force, which acts on the bottom of culinder in the end of 30nd second.

I can't believe, that it is simply F=m*g (m=density*V; V=Q*t)! (here V- volume)
Should I also take into acount dinamic pressure? Pdin=density*(v^2)/2; (here v-velocity) v=sqrt(2*g*H)
F=m*g+pdin*S (S=pi*d^2/4 - area)
Help me please!
 
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Of course u'd need to include the force exerted by dinamical pressure.If u didn't,then the water would not be pouring into the cylinder,but instead being there motioness.

Daniel.
 
Ok.
In this way i receive:
Pstatic=density*g*h1 (h1 - height of the water in the culinder)
Pdinamic = density*(v^2)/2=desity*g*(H-h1) (From H falls the water)
P=Pstatic+Pdin= density*g*H
So it does not depend on the time and consumption of the water!
Is it really correct?
 
Can anybody help? please
 

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