- #1
chriscarson
- 197
- 26
- Homework Statement
- Calculating Force when having the area .
- Relevant Equations
- How can you Calculate Force ?
How can you Calculate Force ?
etotheipi said:I'm note sure what the question is specifically. We have ##\sigma = \frac{F}{A}## and ##\varepsilon = \frac{\Delta L}{L}##, along with the definition of Young's modulus, ##E = \frac{\sigma}{\varepsilon}##.
You can put these into one expression, namely ##E = \frac{FL}{A\Delta L}##.
chriscarson said:the question is to find the force
etotheipi said:So are you after ##F = \frac{AE\Delta L}{L}##?
That's what's called being out by a factor of ten. Can you find the reason for it?chriscarson said:was very close the teacher s answer was 981N mine was 9812.5N
PeroK said:That's what's called being out by a factor of ten. Can you find the reason for it?
chriscarson said:i know you can round it to 3 significant figures but nothing about factor of ten.
PeroK said:You should post your calculation along with a statement of the problem. My guess is you've misplaced a decimal point somewhere.
Young's Modulus, also known as the modulus of elasticity, is a measure of the stiffness of a material. It is defined as the ratio of stress (force per unit area) to strain (deformation per unit length) in a material under tension or compression.
To calculate force using Young's Modulus, you can use the formula F = A x E x ΔL/L, where F is the force applied, A is the cross-sectional area of the material, E is the Young's Modulus, and ΔL/L is the change in length over the original length of the material.
Young's Modulus is typically measured in units of Pascals (Pa) or Newtons per square meter (N/m²). However, it can also be expressed in other units such as gigapascals (GPa) or megapascals (MPa).
The higher the Young's Modulus of a material, the stiffer and more resistant it is to deformation. Materials with lower Young's Modulus, such as rubber, are more flexible and easier to deform.
Young's Modulus is an important property in materials science and engineering. It is used to design and test structures, such as buildings, bridges, and airplanes, to ensure they can withstand the forces they will experience. It is also used in the manufacturing of products, such as car parts and medical devices, to determine the strength and durability of the materials used.